Stoutsburg, Indiana
From Wikipedia, the free encyclopedia
| Stoutsburg | |
|---|---|
| Town | |
  Stoutsburg | |
| Coordinates: 41°11′29″N 87°06′50″W / 41.19139°N 87.11389°WCoordinates: 41°11′29″N 87°06′50″W / 41.19139°N 87.11389°W | |
| Country | United States |
| State | Indiana |
| County | Jasper |
| Township | Wheatfield |
| Elevation[1] | 676 ft (206 m) |
| ZIP code | 46392 |
| FIPS code | 18-73641[2] |
| GNIS feature ID | 449829 |
Stoutsburg used to be an unincorporated town in Wheatfield Township, Jasper County, Indiana. It is now a woodland preserve.
Geography
Stoutsburg is located at 41°11′29″N 87°06′50″W / 41.19139°N 87.11389°W.
References
- ↑ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
- ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
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