Seymourville, West Virginia

From Wikipedia, the free encyclopedia
Seymourville, West Virginia
Unincorporated community
Seymourville, West Virginia
Coordinates: 39°03′25″N 79°06′32″W / 39.05694°N 79.10889°W / 39.05694; -79.10889Coordinates: 39°03′25″N 79°06′32″W / 39.05694°N 79.10889°W / 39.05694; -79.10889
Country United States
State West Virginia
County Grant
Elevation 1,030 ft (310 m)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
Area code(s) 304 & 681
GNIS feature ID 1555594[1]

Seymourville is an unincorporated community in Grant County, West Virginia, United States. Seymourville is 4.5 miles (7.2 km) north of Petersburg.

References


This article is issued from Wikipedia. The text is available under the Creative Commons Attribution/Share Alike; additional terms may apply for the media files.