Sevastopol, Indiana

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Sevastopol
Town
Sevastopol
Coordinates: 41°07′45″N 86°01′08″W / 41.12917°N 86.01889°W / 41.12917; -86.01889Coordinates: 41°07′45″N 86°01′08″W / 41.12917°N 86.01889°W / 41.12917; -86.01889
Country United States
State Indiana
County Kosciusko
Township Franklin
Elevation[1] 879 ft (268 m)
ZIP code 46510
FIPS code 18-68760[2]
GNIS feature ID 443221

Sevastopol is an unincorporated town in Franklin Township, Kosciusko County, Indiana. The community is located in the far southwest corner of the county, five miles from Mentone, seven from Burket, and 15 from Warsaw, the county seat.

Geography

Sevastopol is located at 41°07′45″N 86°01′08″W / 41.12917°N 86.01889°W / 41.12917; -86.01889.


References

  1. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31. 
  2. "American FactFinder". United States Census Bureau. Retrieved 2008-01-31. 


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