Perron's formula

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In mathematics, and more particularly in analytic number theory, Perron's formula is a formula due to Oskar Perron to calculate the sum of an arithmetical function, by means of an inverse Mellin transform.

Statement

Let \{a(n)\} be an arithmetic function, and let

g(s)=\sum _{{n=1}}^{{\infty }}{\frac  {a(n)}{n^{{s}}}}

be the corresponding Dirichlet series. Presume the Dirichlet series to be absolutely convergent for \Re (s)>\sigma _{a}. Then Perron's formula is

A(x)={\sum _{{n\leq x}}}^{{\star }}a(n)={\frac  {1}{2\pi i}}\int _{{c-i\infty }}^{{c+i\infty }}g(z){\frac  {x^{{z}}}{z}}dz.\;

Here, the star on the summation indicates that the last term of the sum must be multiplied by 1/2 when x is an integer. The formula requires c>\sigma _{a} and x>0 real, but otherwise arbitrary.

Proof

An easy sketch of the proof comes from taking Abel's sum formula

g(s)=\sum _{{n=1}}^{{\infty }}{\frac  {a(n)}{n^{{s}}}}=s\int _{{0}}^{{\infty }}A(x)x^{{-(s+1)}}dx.

This is nothing but a Laplace transform under the variable change x=e^{t}. Inverting it one gets Perron's formula.

Examples

Because of its general relationship to Dirichlet series, the formula is commonly applied to many number-theoretic sums. Thus, for example, one has the famous integral representation for the Riemann zeta function:

\zeta (s)=s\int _{1}^{\infty }{\frac  {\lfloor x\rfloor }{x^{{s+1}}}}\,dx

and a similar formula for Dirichlet L-functions:

L(s,\chi )=s\int _{1}^{\infty }{\frac  {A(x)}{x^{{s+1}}}}\,dx

where

A(x)=\sum _{{n\leq x}}\chi (n)

and \chi (n) is a Dirichlet character. Other examples appear in the articles on the Mertens function and the von Mangoldt function.

References

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