Leskov Island (Antarctica)

From Wikipedia, the free encyclopedia
For the island in the South Sandwich Islands, see Leskov Island.

Leskov Island (66°36′S 85°10′E / 66.600°S 85.167°E / -66.600; 85.167Coordinates: 66°36′S 85°10′E / 66.600°S 85.167°E / -66.600; 85.167) is an ice-covered island in the West Ice Shelf of Antarctica, rising to 185 metres (600 ft), 6 nautical miles (11 km) northwest of Mikhaylov Island. It was discovered by the Soviet expedition of 1956, who named it for Lieutenant A. Leskov of the sloop Vostok on the Bellingshausen expedition of 1819–21.[1]

References

  1. ↑ "Leskov Island". Geographic Names Information System, U.S. Geological Survey. Retrieved 2013-06-11. 

 This article incorporates public domain material from the United States Geological Survey document "Leskov Island" (content from the Geographic Names Information System).


This article is issued from Wikipedia. The text is available under the Creative Commons Attribution/Share Alike; additional terms may apply for the media files.