Lake Santee, Indiana

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Lake Santee, Indiana
Census-designated place
Lake Santee, Indiana
Coordinates: 39°24′36″N 85°18′27″W / 39.41000°N 85.30750°W / 39.41000; -85.30750Coordinates: 39°24′36″N 85°18′27″W / 39.41000°N 85.30750°W / 39.41000; -85.30750
Country United States
State Indiana
County Decatur, Franklin
Township Fugit, Salt Creek
Area
  Total 2.8 sq mi (7.3 km2)
  Land 2.5 sq mi (6.4 km2)
  Water 0.3 sq mi (0.9 km2)
Elevation 1,015 ft (309 m)
Population (2010)[1]
  Total 820
ZIP code 47240
FIPS code 18-41444[2]

Lake Santee is an unincorporated town and census-designated place in Decatur and Franklin counties, Indiana, United States. It consists of a housing development centered around a reservoir of the same name. As of the 2010 census, it had a population of 820.[1]

Geography

Lake Santee is located at 39°24′36″N 85°18′27″W / 39.41000°N 85.30750°W / 39.41000; -85.30750 in southeastern Indiana. It is situated 13 miles (21 km) northeast of Greensburg and 12 miles (19 km) northwest of Batesville.

According to the U.S. Census Bureau, the CDP has a total area of 2.8 square miles (7.3 km2), of which 2.5 square miles (6.4 km2) is land and 0.35 square miles (0.9 km2), or 12.60%, is water. The water area consists entirely of Lake Santee, the reservoir.[3]

References

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