Kheralu

From Wikipedia, the free encyclopedia
Kheralu
city
Kheralu
Location in Gujarat, India
Coordinates: 23°53′N 72°37′E / 23.88°N 72.62°E / 23.88; 72.62Coordinates: 23°53′N 72°37′E / 23.88°N 72.62°E / 23.88; 72.62
Country  India
State Gujarat
District Mehsana
Elevation 149 m (489 ft)
Population (2001)
  Total 20,143
Languages
  Official Gujarati, Hindi
Time zone IST (UTC+5:30)

Kheralu is a city and a municipality in Mehsana district in the Indian state of Gujarat. It is a little north of Mahesana Proper town and it is approximately half the size of Mahesana.

Geography

Kheralu is located at 23°53′N 72°37′E / 23.88°N 72.62°E / 23.88; 72.62.[1] It has an average elevation of 149 metres (488 feet). It is the second largest town in its district after Mehsana proper town.[citation needed] It used to have a flowing river which dry now .

Demographics

As of 2001 India census,[2] Kheralu had a population of 20,143. Males constitute 52% of the population and females 48%. Kheralu has an average literacy rate of 68%, higher than the national average of 59.5%: male literacy is 76%, and female literacy is 59%. In Kheralu, 13% of the population is under 6 years of age.

References

  1. Falling Rain Genomics, Inc - Kheralu
  2. "Census of India 2001: Data from the 2001 Census, including cities, villages and towns (Provisional)". Census Commission of India. Archived from the original on 2004-06-16. Retrieved 2008-11-01. 
This article is issued from Wikipedia. The text is available under the Creative Commons Attribution/Share Alike; additional terms may apply for the media files.