Guillaume Raoux

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Guillaume Raoux
Country  France
Residence Boca Raton, Florida, USA
Born (1970-02-14) February 14, 1970
Bagnols-sur-Cèze, France
Height 5'11" (180 cm)
Turned pro 1989
Retired 2000
Plays Right-handed (one-handed backhand)
Prize money $2,449,106
Singles
Career record 179–225
Career titles 1
Highest ranking No. 35 (8 June 1998)
Grand Slam Singles results
Australian Open 4R (1998)
French Open 2R (1995, 1997, 1998)
Wimbledon 3R (1997)
US Open 2R (1991, 1996, 1997, 1998)
Other tournaments
Olympic Games 1R (1996)
Doubles
Career record 102–105
Career titles 4
Highest ranking No. 35 (5 August 1996)
Grand Slam Doubles results
Australian Open 2R (1995, 1996)
French Open QF (1989)
Wimbledon QF (1996)
US Open 3R (1995, 1997)
Last updated on: November 28, 2012.

Guillaume Raoux (born February 14, 1970 in Bagnols-sur-Cèze, Gard) is a retired tennis player from France.

Career

Juniors

Tournament19871988
Junior Grand Slam Tournaments
Australian Open A A
French Open 2R 1R
Wimbledon A F
US Open A 2R

Pro tour

Raoux turned professional in 1989. He represented his native country at the 1996 Summer Olympics in Atlanta, United States, where he was defeated in the first round by Zimbabwe's Byron Black. The right-hander won one singles career title (Brisbane, 1992), and achieved a career-high ATP singles ranking of World No. 35 in June 1998. Raoux reached the fourth round of the 1998 Australian Open and the quarterfinals of the Paris Masters in 1990 and 1997.

He was the first man to be beaten by Roger Federer on the ATP Tour.[1]

References

External links

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