Geodesic curvature

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In Riemannian geometry, the geodesic curvature k_{g} of a curve \gamma measures how far the curve is from being a geodesic. In a given manifold {\bar  {M}}, the geodesic curvature is just the usual curvature of \gamma (see below), but when \gamma is restricted to lie on a submanifold M of {\bar  {M}} (e.g. for curves on surfaces), geodesic curvature refers to the curvature of \gamma in M and it is different in general from the curvature of \gamma in the ambient manifold {\bar  {M}}. The (ambient) curvature k of \gamma depends on two factors: the curvature of the submanifold M in the direction of \gamma (the normal curvature k_{n}), which depends only from the direction of the curve, and the curvature of \gamma seen in M (the geodesic curvature k_{g}), which is a second order quantity. The relation between these is k={\sqrt  {k_{g}^{2}+k_{n}^{2}}}. In particular geodesics on M have zero geodesic curvature (they are "straight"), so that k=k_{n}, which explains why they appear to be curved in ambient space whenever the submanifold is.

Definition

Consider a curve \gamma in a manifold {\bar  {M}}, parametrized by arclength, with unit tangent vector T=d\gamma /ds. Its curvature is the norm of the covariant derivative of T: k=\|DT/ds\|. If \gamma lies on M, the geodesic curvature is the norm of the projection of the covariant derivative DT/ds on the tangent space to the submanifold. Conversely the normal curvature is the norm of the projection of DT/ds on the normal bundle to the submanifold at the point considered.

If the ambient manifold is the euclidean space {\mathbb  {R}}^{n}, then the covariant derivative DT/ds is just the usual derivative dT/ds.

Example

Let M be the unit sphere S^{2} in three dimensional Euclidean space. The normal curvature of S^{2} is identically 1, independently of the direction considered. Great circles have curvature k=1, so they have zero geodesic curvature, and are therefore geodesics. Smaller circles of radius r will have curvature 1/r and geodesic curvature k_{g}={\sqrt  {1-r^{2}}}/r.

Some results involving geodesic curvature

  • The geodesic curvature is no other than the usual curvature of the curve when computed intrinsically in the submanifold M. It does not depend on the way the submanifold M sits in {\bar  {M}}.
  • Geodesics of M have zero geodesic curvature, which is equivalent to saying that DT/ds is orthogonal to the tangent space to M.
  • On the other hand the normal curvature depends strongly on how the submanifold lies in the ambient space, but marginally on the curve: k_{n} only depends on the point on the submanifold and the direction T, but not on DT/ds.
  • In general Riemannian geometry, the derivative is computed using the Levi-Civita connection {\bar  {\nabla }} of the ambient manifold: DT/ds={\bar  {\nabla }}_{T}T. It splits into a tangent part and a normal part to the submanifold: {\bar  {\nabla }}_{T}T=\nabla _{T}T+({\bar  {\nabla }}_{T}T)^{\perp }. The tangent part is the usual derivative \nabla _{T}T in M (it is a particular case of Gauss equation in the Gauss-Codazzi equations), while the normal part is {\mathrm  {I\!I}}(T,T), where {\mathrm  {I\!I}} denotes the second fundamental form.

See also

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