Franks Field, Wisconsin
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Franks Field, Wisconsin | |
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Census-designated place | |
Franks Field, Wisconsin | |
Coordinates: 46°33′08″N 90°35′56″W / 46.55222°N 90.59889°WCoordinates: 46°33′08″N 90°35′56″W / 46.55222°N 90.59889°W | |
Country | United States |
State | Wisconsin |
County | Ashland |
Area | |
• Total | 1.266 sq mi (3.28 km2) |
• Land | 1.266 sq mi (3.28 km2) |
• Water | 0 sq mi (0 km2) |
Elevation | 810 ft (250 m) |
Population (2010)[1] | |
• Total | 154 |
• Density | 120/sq mi (47/km2) |
Time zone | Central (CST) (UTC-6) |
• Summer (DST) | CDT (UTC-5) |
Area code(s) | 715 & 534 |
GNIS feature ID | 2585063[2] |
Franks Field is a census-designated place in the town of Sanborn, Ashland County, Wisconsin, United States. Its population was 154 as of the 2010 census.[1] Franks Field is located on the Bad River Indian Reservation.
References
- ↑ 1.0 1.1 "American FactFinder". U.S. Census Bureau. Retrieved 4 April 2011.
- ↑ U.S. Geological Survey Geographic Names Information System: Franks Field, Wisconsin
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