Fountaintown, Indiana
From Wikipedia, the free encyclopedia
Fountaintown | |
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Town | |
Fountaintown | |
Coordinates: 39°41′41″N 85°46′59″W / 39.69472°N 85.78306°WCoordinates: 39°41′41″N 85°46′59″W / 39.69472°N 85.78306°W | |
Country | United States |
State | Indiana |
County | Shelby |
Township | Van Buren |
Elevation | 850 ft (260 m) |
ZIP code | 46130 |
FIPS code | 18-25162[1] |
GNIS feature ID | 434718[2] |
Fountaintown is an unincorporated town in Van Buren Township, Shelby County, Indiana.
Geography
Fountaintown is located at 39°41′41″N 85°46′59″W / 39.69472°N 85.78306°W.
References
- ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
- ↑ "Fountaintown, Indiana". Geographic Names Information System, U.S. Geological Survey. Retrieved 2009-10-17.
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