Cleveland, Indiana
From Wikipedia, the free encyclopedia
Cleveland | |
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Town | |
Cleveland | |
Coordinates: 39°47′25″N 85°38′41″W / 39.79028°N 85.64472°WCoordinates: 39°47′25″N 85°38′41″W / 39.79028°N 85.64472°W | |
Country | United States |
State | Indiana |
County | Hancock |
Township | Jackson |
Elevation | 971 ft (296 m) |
ZIP code | 46140 |
FIPS code | 18-13546[1] |
GNIS feature ID | 432645[2] |
Cleveland is an unincorporated town in Jackson Township, Hancock County, Indiana.
Geography
Cleveland is located at 39°47′25″N 85°38′41″W / 39.79028°N 85.64472°W.
References
- ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
- ↑ "Cleveland, Indiana". Geographic Names Information System, U.S. Geological Survey. Retrieved 2009-10-10.
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