Cape Sandy, Indiana
From Wikipedia, the free encyclopedia
Cape Sandy | |
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Town | |
Cape Sandy | |
Coordinates: 38°09′03″N 86°22′15″W / 38.15083°N 86.37083°WCoordinates: 38°09′03″N 86°22′15″W / 38.15083°N 86.37083°W | |
Country | United States |
State | Indiana |
County | Crawford |
Township | Ohio |
Elevation | 741 ft (226 m) |
ZIP code | 47137 |
FIPS code | 18-10180[1] |
GNIS feature ID | 432118[2] |
Cape Sandy is an unincorporated community in Ohio Township, Crawford County, Indiana.
Geography
Cape Sandy is located at 38°09′03″N 86°22′15″W / 38.15083°N 86.37083°W.
References
- ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
- ↑ "Cape Sandy, Indiana". Geographic Names Information System, U.S. Geological Survey. Retrieved 2009-10-10.
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See also
- List of cities and towns along the Ohio River
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