Bucktown, Indiana

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Bucktown
Unincorporated town
Sullivan County's location in Indiana
Bucktown
Location in Sullivan County, Indiana
Coordinates: 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W / 38.99472; -87.26000Coordinates: 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W / 38.99472; -87.26000
Country United States
State Indiana
County Sullivan
Township Jefferson
Elevation 594 ft (181 m)
GNIS feature ID 431756[1]

Bucktown is an unincorporated town in Jefferson Township, Sullivan County, Indiana. It is part of the Terre Haute Metropolitan Statistical Area.

Geography

Bucktown is located at 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W / 38.99472; -87.26000.

References

  1. "Bucktown, Indiana". Geographic Names Information System, U.S. Geological Survey. Retrieved 2010-08-18. 


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