In computer science, the Wagner–Fischer algorithm is a dynamic programming algorithm that measures the Levenshtein distance between two strings of characters.
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The Wagner-Fischer algorithm computes Levenshtein distance based on the observation that if we reserve a matrix to hold the Levenshtein distances between all prefixes of the first string and all prefixes of the second, then we can compute the values in the matrix by flood filling the matrix, and thus find the distance between the two full strings as the last value computed.
A straightforward implementation, as pseudocode for a function LevenshteinDistance that takes two strings, s of length m, and t of length n, and returns the Levenshtein distance between them:
int LevenshteinDistance(char s[1..m], char t[1..n]) { // for all i and j, d[i,j] will hold the Levenshtein distance between // the first i characters of s and the first j characters of t; // note that d has (m+1)x(n+1) values declare int d[0..m, 0..n] for i from 0 to m d[i, 0] := i // the distance of any first string to an empty second string for j from 0 to n d[0, j] := j // the distance of any second string to an empty first string for j from 1 to n { for i from 1 to m { if s[i] = t[j] then d[i, j] := d[i-1, j-1] // no operation required else d[i, j] := minimum ( d[i-1, j] + 1, // a deletion d[i, j-1] + 1, // an insertion d[i-1, j-1] + 1 // a substitution ) } } return d[m,n] }
Two examples of the resulting matrix (hovering over a number reveals the operation performed to get that number):
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The invariant maintained throughout the algorithm is that we can transform the initial segment s[1..i]
into t[1..j]
using a minimum of d[i,j]
operations. At the end, the bottom-right element of the array contains the answer.
As mentioned earlier, the invariant is that we can transform the initial segment s[1..i]
into t[1..j]
using a minimum of d[i,j]
operations. This invariant holds since:
s[1..i]
can be transformed into the empty string t[1..0]
by simply dropping all i
characters. Similarly, we can transform s[1..0]
to t[1..j]
by simply adding all j
characters.s[i] = t[j]
, and we can transform s[1..i-1]
to t[1..j-1]
in k
operations, then we can do the same to s[1..i]
and just leave the last character alone, giving k
operations.s[1..i]
to t[1..j-1]
in k
operations, then we can simply add t[j]
afterwards to get t[1..j]
in k+1
operations (insertion).s[1..i-1]
to t[1..j]
in k
operations, then we can remove s[i]
and then do the same transformation, for a total of k+1
operations (deletion).s[1..i-1]
to t[1..j-1]
in k
operations, then we can do the same to s[1..i]
, and exchange the original s[i]
for t[j]
afterwards, for a total of k+1
operations (substitution).s[1..n]
into t[1..m]
is of course the number required to transform all of s
into all of t
, and so d[n,m]
holds our result.This proof fails to validate that the number placed in d[i,j]
is in fact minimal; this is more difficult to show, and involves an argument by contradiction in which we assume d[i,j]
is smaller than the minimum of the three, and use this to show one of the three is not minimal.
Possible improvements to this algorithm include:
j
.[0,1]
.cost
values can be computed in parallel, and the algorithm can be adapted to perform the minimum
function in phases to eliminate dependencies.The Levenshtein distance has several simple upper and lower bounds that are useful in applications which compute many of them and compare them. These include: