In complex analysis, a branch of mathematics, the Koebe 1/4 theorem states that the image of an injective analytic function from the unit disk onto a subset of the complex plane contains the disk whose center is and whose radius is . The theorem is named after Paul Koebe, who conjectured the result in 1907. The theorem was proven by Ludwig Bieberbach in 1914. The Koebe function ƒ(z) = z/(1 − z)2 shows that the constant 1/4 in the theorem cannot be improved.
A related result is the Schwarz lemma, and a notion related to both is conformal radius.
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Suppose that
is univalent in Then
In fact, if r > 1, the complement of the image of the disk |z| > r is a bounded domain X(r). Its area is given by
Since the area is positive, the result follows by letting r decrease to 1. The above proof shows quality holds if and only if the complement of the image of g has zero area, i.e. Lebesgue measure zero.
This result was proved in 1914 by the Swedish mathematician Thomas Hakon Gronwall.
Let
be univalent in . Then
This follows by applying Gronwall's area theorem to the odd univalent function
Equality holds if and only if g is a rotation of the Koebe function.
This result was proved by Ludwig Bieberbach in 1916 and provided the basis for his celebrated conjecture that |an| ≤ n, proved in 1985 by Louis de Branges.
Applying an affine map, it can be assumed that
so that
If w is not in , then
is univalent in .
Applying the coefficient inequality to f and h gives
so that
The Koebe distortion theorem gives a series of bounds for a univalent function and its derivative. It is a direct consequence of Bieberbach's inequality for the second coefficient and the Koebe quarter theorem.[1]
Let f(z) be a univalent function on |z| < 1 normalized so that f(0) = 0 and f'(0) = 0 and let r = |z|. Then
with equality if and only if f is a Koebe function