Cumberland is a town in Barron County in the U.S. state of Wisconsin. The population was 2280 at the 2000 census. The City of Cumberland is located partially within the town.
According to the United States Census Bureau, the town has a total area of 33.1 square miles (85.6 km²), of which, 32.1 square miles (83.2 km²) of it is land and 0.9 square miles (2.5 km²) of it (2.87%) is water.
As of the census[1] of 2000, there were 942 people, 360 households, and 288 families residing in the town. The population density was 29.3 people per square mile (11.3/km²). There were 425 housing units at an average density of 13.2 per square mile (5.1/km²). The racial makeup of the town was 99.47% White, 0.11% Black or African American, 0.11% Native American, 0.11% from other races, and 0.21% from two or more races. Hispanic or Latino of any race were 0.64% of the population.
There were 360 households out of which 30.8% had children under the age of 18 living with them, 69.7% were married couples living together, 6.9% had a female householder with no husband present, and 20.0% were non-families. 15.8% of all households were made up of individuals and 8.3% had someone living alone who was 65 years of age or older. The average household size was 2.62 and the average family size was 2.92.
In the town the population was spread out with 25.2% under the age of 18, 5.8% from 18 to 24, 26.9% from 25 to 44, 24.7% from 45 to 64, and 17.4% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 115.6 males. For every 100 females age 18 and over, there were 108.0 males.
The median income for a household in the town was $40,521, and the median income for a family was $42,125. Males had a median income of $30,893 versus $24,844 for females. The per capita income for the town was $18,061. About 6.3% of families and 8.1% of the population were below the poverty line, including 8.7% of those under age 18 and 7.4% of those age 65 or over.
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