Amherst is a town in Portage County, Wisconsin, United States. The population was 1,435 at the 2000 census.
According to the United States Census Bureau, the town has a total area of 38.5 square miles (99.7 km²), of which, 38.0 square miles (98.4 km²) of it is land and 0.5 square miles (1.3 km²) of it (1.35%) is water.
As of the census[1] of 2000, there were 1,435 people, 494 households, and 390 families residing in the town. The population density was 37.8 people per square mile (14.6/km²). There were 556 housing units at an average density of 14.6 per square mile (5.7/km²). The racial makeup of the town was 98.19% White, 0.07% Black or African American, 0.21% Native American, 0.98% Asian, 0.14% from other races, and 0.42% from two or more races. 0.35% of the population were Hispanic or Latino of any race.
There were 494 households out of which 37.9% had children under the age of 18 living with them, 70.6% were married couples living together, 3.8% had a female householder with no husband present, and 20.9% were non-families. 17.0% of all households were made up of individuals and 6.9% had someone living alone who was 65 years of age or older. The average household size was 2.80 and the average family size was 3.17.
In the town the population was spread out with 26.1% under the age of 18, 6.3% from 18 to 24, 26.6% from 25 to 44, 28.5% from 45 to 64, and 12.5% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 107.4 males. For every 100 females age 18 and over, there were 100.9 males.
The median income for a household in the town was $50,435, and the median income for a family was $55,313. Males had a median income of $37,784 versus $25,536 for females. The per capita income for the town was $19,751. About 3.4% of families and 6.8% of the population were below the poverty line, including 2.1% of those under age 18 and 27.3% of those age 65 or over.
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