User talk:Xiaodai

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Hi my name is Zhuo Jia Dai. My interests include soccer, computer games, mathematics and computer programming. I'm currently doing Bachelor of Computer Science at the university of sydney.

Hello Xiaodai, and welcome to the english Wikipedia. Here are some helpful pages:

If you have further questions, feel free to ask them on

Have a lot of fun -- Cordyph 14:00 22 Jul 2003 (UTC)

Hello. Could you attend to the minor fix needed in the illustration accompanying the article titled mean value theorem? Thanks. (See the illustration's talk page for details.) Michael Hardy 22:01, 1 May 2004 (UTC)

Contents

[edit] Wikipedia:WikiProject Sydney

Want to join? I'm still formulating policy. I see you live in Campsie - perhaps you could contribute to the Sydney suburbs thing we're trying to get off the ground! Incidently, there is a message board Wikipedia:Australian wikipedians' notice board - Ta bu shi da yu 06:09, 23 Sep 2004 (UTC)

[edit] Football links

Hi Xiaodai,

Greetings from another USyd student.

There is a dedicated article for football around the world; this is the best place for links to national football articles, such as Football in China, rather than the overview article Football (soccer).

Cheers, --Daveb 12:31, 1 May 2005 (UTC)

[edit] Image copyright problem with Image:Sydney_FC_Home_Strip_05-06.png

Thanks for uploading Image:Sydney_FC_Home_Strip_05-06.png. However, the image may soon be deleted unless we can determine the copyright holder and copyright status. The Wikimedia Foundation is very careful about the images included in Wikipedia because of copyright law (see Wikipedia's Copyright policy).

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This is an automated notice by OrphanBot. If you have questions about copyright tagging of images, post on Wikipedia talk:Image copyright tags or User talk:Carnildo/images. 02:53, 2 March 2006 (UTC)

[edit] Great Deluge Algorithm

I'd updated the article a little bit, hopefully with relevant info. Destription of the algorithm would be quite helpful. Pavel Vozenilek 02:05, 8 October 2006 (UTC)

[edit] Unspecified source for Image:Mvt without text.png

Thanks for uploading Image:Mvt without text.png. I noticed that the file's description page currently doesn't specify who created the content, so the copyright status is unclear. If you did not create this file yourself, then you will need to specify the owner of the copyright. If you obtained it from a website, then a link to the website from which it was taken, together with a restatement of that website's terms of use of its content, is usually sufficient information. However, if the copyright holder is different from the website's publisher, then their copyright should also be acknowledged.

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[edit] Image:Jen_and_me.JPG listed for deletion

An image or media file that you uploaded or altered, Image:Jen_and_me.JPG, has been listed at Wikipedia:Images and media for deletion. Please look there to see why this is (you may have to search for the title of the image to find its entry), if you are interested in it not being deleted. Thank you. User:Gay Cdn (talk) (Contr) 19:18, 4 May 2007 (UTC)

[edit] Hello

I've seen your important contributions for the article Recurrence relation. I'm looking for the general (non-iterative) non-trigonometric expression for the exact trigonometric constants of the form: \begin{align}\cos \frac{\pi}{2^n}\end{align}, when n is natural (and is not given in advance). Do you know of any such general (non-iterative) non-trigonometric expression? (note that any exponential-expression-over-the-imaginaries is also excluded since it's trivially equivalent to a real-trigonometric expression).

  • Let me explain: if we choose n=1 then the term \begin{align}\cos \frac{\pi}{2^n}\end{align} becomes "0", which is a simple (non-trigonometric) constant. If we choose n=2 then the term \begin{align}\cos \frac{\pi}{2^n}\end{align} becomes \begin{align}\frac{1}{\sqrt{2}}\end{align}, which is again a non-trigonometric expression. etc. etc. Generally, for every natural n, the term \begin{align}\cos \frac{\pi}{2^n}\end{align} becomes a non-trigonometric expression. However, when n is not given in advance, then the very expression \begin{align}\cos \frac{\pi}{2^n}\end{align} per se - is a trigonometric expression. I'm looking for the general (non-iterative) non-trigonometric expression equivalent to \begin{align}\cos \frac{\pi}{2^n}\end{align}, when n is not given in advance. If not for the cosine - then for the sine or the tangent or the cotangent.

Eliko (talk) 08:26, 31 March 2008 (UTC)