Wolfram's 2-state 3-symbol Turing machine

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In his A New Kind of Science, Stephen Wolfram found a universal 2-state 5-color Turing machine, and conjectured that a particular 2-state 3-color Turing machine (hereinafter (2,3) Turing machine) might be universal as well.

On May 14, 2007, Wolfram announced a $25,000 prize[1] to be won by the first person to prove or disprove the universality of the (2,3) Turing machine. According to Wolfram, the purpose of the prize was to encourage research to help answer foundational questions associated with the structure of what he calls the "computational universe".

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[edit] Description

In each state, the machine reads the bit under the head and executes the instructions in the following table (where Pn prints bit n, L and R are left and right respectively, and A and B mean "switch to that state").


A B
0 P1,R,B P2,L,A
1 P2,L,A P2,R,B
2 P1,L,A P0,R,A

The (2,3) Turing machine:

  • Has no halt state;
  • Is trivially related to 24 other machines by interchange of states, colors and directions.

The (2,3) Turing machine is unusually interesting, because it is known that standard (2,2) machines cannot be universal as discussed briefly by Minsky (1967). Hence making the (2,3) Turing machine the smallest possible universal Turing machine.

location: left

The state of the head (up or down droplet) and the pattern of colour (orange, yellow and white) in a given row depends solely on the content of the row immediately above it.

Even though the machine has a head with only two states, and a tape that can hold only three colours (depending on the initial content of the tape), the machine's output can still be remarkably complex.[2]

[edit] Proof of universality

On 24 October 2007, it was announced that Alex Smith, a student in electronics and computing at the University of Birmingham (UK), proved that the (2,3) Turing machine is universal and thus won Wolfram's prize described above[3]. The proof showed that the machine is equivalent to a variant of a tag system already known to be universal. Smith first constructed a sequence of rule systems showing that the (2,3) Turing machine is capable of arbitrary finite computations. He then employed a novel approach to extend that construction to unbounded computations. The proof proceeds in two stages. The first part emulates the finite evolution of any two-color cyclic tag system. The emulation is a composite of a series of emulations involving the indexed rule systems 'system 0' through 'system 5'. Each rule system emulates the next one in the sequence. Smith then showed that even though the initial condition of the (2,3) Turing machine is not repetitive, the construction of that initial condition is not universal. Hence the (2,3) Turing machine is universal.

Vaughan Pratt disputed the correctness of this proof in a public list of discussion[4], noting that similar techniques would allow a linear bounded automaton to be universal, which would contradict a known non-universality result due to Noam Chomsky. In their reply to Pratt, Wolfram Research and Alex Smith rejected Pratt's claim.[1][2][3][4]

Wolfram claims that Smith's proof is another piece of evidence for Wolfram's general Principle of Computational Equivalence (PCE).[5] That principle states that if one sees behavior that is not obviously simple, the behavior will correspond to a computation that is in a sense "maximally sophisticated."[6] Smith's proof has unleashed a debate on the precise operational conditions a Turing machine must satisfy in order for it to be candidate universal machine.

A universal (2,3) Turing machine has conceivable applications[7]. For instance, a machine that small and simple can be embedded or constructed using a small number of particles or molecules. But the "compiler" Smith's algorithm implies does not produce compact or efficient code, at least for anything but the simplest cases. Hence the resulting code tends to be astronomically large and very inefficient. Whether there exist more efficient codings enabling the (2,3) Turing machine to compute more rapidly is an open question.

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