Talk:Virial theorem

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For the power-law relationship given is the number 'n' appearing in the exponent required to be a natural number? I suppose it is, otherwise any force should be described as satisfying a power-law. But then I've read numerous papers on 1/f noise discussing a 3/2 power law relation. Mandelbrot described fractional power-laws in a paper with John van Ness in the 1950's. So what is it that makes natural number power laws so different from real number power laws?

Reply: Why is it true that any force can satisfy a power-law with a non-natural exponent? Does this just happen to be the case for every force in existance? That would surprise me, though I cannot currently think of a counter example. Certainly arbitrary functions cannot be described as power laws.
Never heard of a Taylor expansion, then?
I think \overline{K} = \frac{n+1}{2} \overline{V} holds also for fractional n. It assumes V = arn + 1, not a sum of powers.--Patrick 07:55, 13 October 2005 (UTC)
A Taylor expansion is a sum of power-laws, not a single power law. The strong force and weak force are not power laws, but drop precipitously at larger distances. The force between two magnetic dipoles is proportional to the inverse-cube of the distance, but also proportional to a factor determined by the relative orientations of the dipoles and the separation between them. 128.165.112.42 15:04, 25 May 2006 (UTC)

After the copyright situation is resolved, a possible good link to add is John Baez's explanation 128.165.112.42 15:04, 25 May 2006 (UTC)

Contents

[edit] Have you heard of Copyright?

I wonder who wrote this page, but I'd like to remind him that copyright should be respected.

If you compare this page with Goldstein's "Classical Mechanics" p.70, you'd understand by point.

Besides, if you intend to copy anyway, please state "if the force is central" just before "If V is a power-law function of r". This can't be omitted, because you are using the same r to represent the position vector and the radius vector ambiguously.

I put a notice at Wikipedia:Copyright problems but I don't know the proper procedure for this. 80.203.45.67 14:00, 8 April 2006 (UTC)
Which edition? Zarniwoot 00:20, 14 May 2006 (UTC)

[edit] Nomenclature

I don't like the nomenclature K for the kinetic energy. Remember that K is still often used for force, too, especially in Special Relativity, given that until the 40s, German was especially important in physics. In German, force is named Kraft and the relativistic 4-force is often written as K.

For the kinetic energy, the nomenclature KE (when not E(kin) or something like that) is much better. However, E would be very good to appear, since the official term for energy is E or W (of work). I think, an often used abbreviation for kinetic energy is T. N.M.B.R.Nbez 11:06, 7 May 2006 (UTC)

[edit] Copyvio

I've reverted to the revision (cur) (last) 03:08, 6 May 2004 158.193.210.45, as per concerns raised above that this is a copyright violation of "Classical Mechanics". As I don't have a copy of the book, I'm unable to check what exactly is a copyright violation.

Please see this for a list of differences between that version and the pre-copyright violation noted version. I've also restored the interwiki links as well as the external links to the version right before it was noted as a copyright violation. Jude (talk,contribs,email) 03:10, 15 May 2006 (UTC)

[edit] No copyvio; have fun!

Hi all, I re-wrote this article from scratch without looking at any outside sources (e.g., books, articles or websites), so there should be no copyright problem now. I did keep the G notation for the virial, but that's about the only hold-over. I'm clueless about how the virial theorem has been used in other settings (e.g., for gases or in quantum mechanics), though, so I'm looking forward to your additions! :D WillowW 10:51, 9 July 2006 (UTC)

[edit] Intro needed?

Something about its significance? —Preceding unsigned comment added by HairyDan (talk • contribs) 22:08, 17 October 2006 (UTC)

I made an try at this; does it seem good to you? Willow 23:06, 17 October 2006 (UTC)

[edit] A little mistake in the etymology

This not exactly a technical issue, but for precision's sake... Although "virial" actually comes from "vis" (force, strength), the Latin substantive is highly irregular, and the genitive form is "roboris" (which was a genitive borrowed, quite curiously, from "robur, roboris", oak). The quoted genitive "viris" doesn't actually exist, and "roboris" would only be confusing... I have simply deleted the genitive.

Massimo 10:43, 18 December 2006 (UTC)

Wow, that's a surprise — thanks for catching that! I knew that vis was irregular in some cases (e.g., vim and vi) but I had so often read the nominative plural vires that I just assumed that there was a corresponding genitive singular. :( Thanks very much, Massimo; I love the way Wikipedia helps us to help each other and learn new things from each other. :) Warm wishes for the holidays, Willow (a distant relative of Quercus robur ;) 15:31, 18 December 2006 (UTC)

[edit] Sign conventions?

When I first learned the viral theorem, it was in the form 2T+V=0; this is because the usual convention is for the potential energy V of a bound system to be negative. It appears that the statement of the theorem in the article regards V to be of the opposite sign to the usual convention. This needs to be discussed. Bill Jefferys 03:56, 6 March 2007 (UTC)

Hi Bill,
Thanks for being so careful in cross-checking the article! The form you learned pertains to gravitational or electromagnetic potential energy and is entirely correct. But the formula in the text is also correct, since n=-1 for gravity and Coulomb's law. If you check the derivation carefully — which I would appreciate very much — I hope you'll find that no sign error has been made. Thanks again! :) Willow 10:36, 29 March 2007 (UTC)

[edit] Virial radius

In the section on the virial radius formula, "H" and "G" should be defined immediately before or after the formula. I'd do it myself, but I'm not sure what H is! A reference would also be good...perhaps one of the "references" or "additional readings" already listed would work? Finally, it could use a sentence giving some context as to why the virial radius is defined the way it is, and why it's a useful thing to think about (for example, is the factor of 200 arbitrary?) Steve 15:05, 16 July 2007 (UTC)

I tried to fix it some, e.g. indicating that the factor 200 is arbitrary, but I find this section rather suspect nonetheless. --Art Carlson 20:45, 18 July 2007 (UTC)

[edit] Who proved the virial theorem?

This is a great article, but how about a little more history? It says Clausius gave the virial theorem it's definition. Does this mean he originated it? Proved it? If not, who did? --Chetvorno 07:48, 21 August 2007 (UTC)

[edit] KE / PE relationship

Would it be of interest for this article to reference and state simply why KE is equal to PE for a pendulum, spring, water wave, etc., and why KE is not equal to PE for orbital mechanics, Bohr atom, etc.? 50MWdoug (talk) 07:24, 31 March 2008 (UTC)

[edit] n \langle V_{TOT} \rangle = \langle V_{TOT} \rangle?

I believe that the statement 2 \langle T \rangle = n \langle V_{TOT} \rangle in the beginning, where VTOT is said to be total potential energy of the system, to be correct the subscript of VTOT should be Vn so that n \langle V_{n} \rangle = \langle V_{TOT} \rangle. Thus making \langle V_{n} \rangle the time average potential energy of the particle n, and the sum of all such particles in the system equal to \langle V_{TOT} \rangle, the total time averaged potential energy of the system.

If someone could verify this to be true as well, it would be greatly appreciated.

Basilf1 (talk) 18:50, 13 May 2008 (UTC)