Talk:Vandermonde's identity
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[edit] Chu-Vandermonde identity sum bound
For the Chu-Vandermonde identity the sum should be from k=0 to n not infinity right? --Ray andrew 02:23, 27 September 2007 (UTC)
- The sum is finite only if n is an integer. If n is a general complex value, then the sum runs to infinity. There's no difference ... when n is an integer, all of the higher order terms are zero anyway. linas (talk) 15:03, 25 March 2008 (UTC)
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- Errr ... I believe that the identity should hold for general complex n, which would follow from Gausses hypergeometric function identity, although I have not tried to check that for any forehead-slapping gotcha's (e.g. some wacky violation of Carlson's theorem.) linas (talk) 15:10, 25 March 2008 (UTC)
[edit] Merge from Vandemonde's formula
I suppose that Vandemonde is a misspelling for Vandermonde. Based on http://mathworld.wolfram.com/VandermondesFormula.html it seems that it relates to the Chu-Vandermonde identity. If appropriate, please merge content. —Leo Laursen ( T ¦ C ) 17:27, 30 January 2008 (UTC)