United States presidential election in Missouri, 1860
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This article describes the United States presidential election, 1860, in Missouri.
Missouri has been voting in presidential elections since 1820. Since 1904, Missouri has voted for the eventual winner of the election in a presidential election, with the single exception of the 1956 election.
| Presidential Candidate | Running Mate | Party | Electoral Vote (EV) | Popular Vote (PV) | |
|---|---|---|---|---|---|
| Stephen Douglas | Herschel Johnson | Democratic | 9[1] | 58,801 | 35.52% |
| John Bell | Edward Everett | Constitutional Union | 0 | 58,372 | 35.26% |
| John Breckenridge | Joseph Lane | Southern Democrat | 0 | 31,362 | 18.94% |
| Abraham Lincoln | Hannibal Hamlin | Republican | 0 | 17,028 | 10.28% |
Statewide winner in bold. See main article : U.S. presidential election, 1860.
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