Unitary group

From Wikipedia, the free encyclopedia

Groups

Basic notions
Subgroup Normal subgroup Quotient group Group homomorphism (semi-)direct product direct sum

Discrete groups
Classification of finite simple groups Cyclic group Z_n Alternating group A_n Sporadic groups Mathieu group M_11..12,M_22..24 Conway group Co_1..3 Janko group J_1..4 Fischer group F_22..24 Baby Monster group B Monster group M

Continuous groups
Lie group General linear group GL(n) Special linear group SL(n) Orthogonal group O(n) Special orthogonal group SO(n) Unitary group U(n) Special unitary group SU(n) Symplectic group Sp(n) E₆ E₇ E₈ F₄ G₂ SL₂ Lorentz group Poincaré group

Infinite dimensional groups
conformal group diffeomorphism group Quantum group O(∞) SU(∞) Sp(∞)

This box: view • talk • edit

In mathematics, the unitary group of degree n, denoted U(n), is the group of n×n unitary matrices, with the group operation that of matrix multiplication. The unitary group is a subgroup of the general linear group GL(n, C).

In the simple case n = 1, the group U(1) corresponds to the circle group, consisting of all complex numbers with absolute value 1 under multiplication. All the unitary groups contain copies of this group.

The unitary group U(n) is a real Lie group of dimension n². The Lie algebra of U(n) consists of complex n×n skew-Hermitian matrices, with the Lie bracket given by the commutator.

The general unitary group (also called the group of unitary similitudes) consists of all matrices $A$ such that $A * A$ is a nonzero multiple of the identity matrix, and is just the product of the unitary group with the group of all positive multiples of the identity matrix.

1 Properties
2 Topology
3 2 out of 3 property
4 G-structure: almost Hermitian
5 Generalizations
6 Classifying space
7 References
8 See also

[edit] Properties

Since the determinant of a unitary matrix is a complex number with norm 1, the determinant gives a group homomorphism

$\det\colon \mbox{U}(n) \to \mbox{U}(1)$

The kernel of this homomorphism is the set of unitary matrices with unit determinant. This subgroup is called the special unitary group, denoted SU(n). We then have a short exact sequence of Lie groups:

$1\to\mbox{SU}(n)\to\mbox{U}(n)\to\mbox{U}(1)\to 1$

This short exact sequence splits so that U(n) may be written as a semidirect product of SU(n) by U(1). Here the U(1) subgroup of U(n) consists of matrices of the form $\mbox{diag}(e^{i\theta},1,1,\ldots,1)$ .

The unitary group U(n) is nonabelian for n > 1. The center of U(n) is the set of scalar matrices λI with λ ∈ U(1). This follows from Schur's lemma. The center is then isomorphic to U(1). Since the center of U(n) is a 1-dimensional abelian normal subgroup of U(n), the unitary group is not semisimple.

[edit] Topology

The unitary group U(n) is endowed with the relative topology as a subset of M_n(C), the set of all n×n complex matrices, which is itself homeomorphic to a 2n²-dimensional Euclidean space.

As a topological space, U(n) is both compact and connected. The compactness of U(n) follows from the Heine-Borel theorem and the fact that it is a closed and bounded subset of M_n(C). To show that U(n) is connected, recall that any unitary matrix A can be diagonalized by another unitary matrix S. Any diagonal unitary matrix must have complex numbers of absolute value 1 on the main diagonal. We can therefore write

$A = S\,\mbox{diag}(e^{i\theta_1},\dots,e^{i\theta_n})\,S^{-1}.$

A path in U(n) from the identity to A is then given by

$t\mapsto S\,\mbox{diag}(e^{it\theta_1},\dots,e^{it\theta_n})\,S^{-1}.$

The unitary group is not simply connected; the fundamental group of U(n) is infinite cyclic for all n:

$\pi_1(U(n)) \cong \mathbf{Z}.$

The first unitary group U(1) is topologically a circle, which is well known to have a fundamental group isomorphic to Z, and the inclusion map $U(n) \to U(n+1)$ is an isomorphism on $π 1$ . (It has quotient the Stiefel manifold.)

The determinant map $\mbox{det}\colon \mbox{U}(n) \to \mbox{U}(1)$ induces an isomorphism of fundamental groups, with the splitting $\mbox{U}(1) \to \mbox{U}(n)$ inducing the inverse.

[edit] 2 out of 3 property

The unitary group is the 3-fold intersection of the orthogonal, symplectic, and complex groups:

$U(n) = O(2n) \cap GL(n,\mathbf{C}) \cap Sp(2n)$

Thus a unitary structure can be seen as an orthogonal structure, a complex structure, and a symplectic structure, which are required to be compatible (meaning that one uses the same J in the complex structure and the symplectic form, and that this J is orthogonal; writing all the groups as matrix groups fixes a J (which is orthogonal) and ensures compatibility).

In fact, it is the intersection of any two of these three; thus a compatible orthogonal and complex structure induce a symplectic structure, and so forth. ^[1] ^[2]

At the level of equations, this can be seen as follows:

Symplectic:

A T J A = J

Complex:

A - 1 J A = J

Orthogonal:

A T = A - 1

Any two of these equations implies the third.

At the level of forms, this can be seen by decomposing a Hermitian form into its real and imaginary parts: the real part is symmetric (orthogonal), and the imaginary part is skew-symmetric (symplectic)—and these are related by the complex structure (which is the compatibility). On an almost Kähler manifold, one can write this decomposition as $h = g + i ω$ , where h is the Hermitian form, g is the Riemannian metric, i is the almost complex structure, and $ω$ is the almost symplectic structure.

From the point of view of Lie groups, this can partly be explained as follows: $O (2 n)$ is the maximal compact subgroup of $GL(2n,\mathbf{R})$ , and $U (n)$ is the maximal compact subgroup of both $GL(n,\mathbf{C})$ and $S p (2 n)$ . Thus the intersection of $O(2n) \cap GL(n,\mathbf{C})$ or $O(2n) \cap Sp(2n)$ is the maximal compact subgroup of both of these, so $U (n)$ . From this perspective, what is unexpected is the intersection $GL(n,\mathbf{C}) \cap Sp(2n) = U(n)$ .

[edit] G-structure: almost Hermitian

In the language of G-structures, a manifold with a $U(n)$ -structure is an almost Hermitian manifold.

[edit] Generalizations

From the point of view of Lie theory, the classical unitary group is a real form of the Steinberg group ${}^2\!A_n$ , which is an algebraic group that arises from the combination of the diagram automorphism of the general linear group (reversing the Dynkin diagram $A n$ , which corresponds to transpose inverse) and the field automorphism of the extension $\mathbf{C}/\mathbf{R}$ (namely complex conjugation). Both these automorphisms are automorphisms of the algebraic group, have order 2, and commute, and the unitary group is the fixed points of the product automorphism, as an algebraic group. The classical unitary group is a real form of this group, corresponding to the standard Hermitian form $Ψ$ , which is positive definite.

This can be generalized in a number of ways:

generalizing to other Hermitian forms yields indefinite unitary groups $\operatorname{U}(p,q)$ ;
the field extension can be replaced by any degree 2 separable algebra, most notably a degree 2 extension of a finite field;
generalizing to other diagrams yields other groups of Lie type, namely the other Steinberg groups ${}^2\!D_n, {}^2\!E_6, {}^3\!D_4,$ (in addition to ${}^2\!A_n$ ) and Suzuki-Ree groups ${}^2\!B_2\left(2^{2n+1}\right), {}^2\!F_4\left(2^{2n+1}\right), {}^2\!G_2\left(3^{2n+1}\right)$ ;
considering a generalized unitary group as an algebraic group, one can take its points over various algebras.

[edit] Indefinite forms

Analogous to the indefinite orthogonal groups, one can define an indefinite unitary group, by considering the transforms that preserve a given Hermitian form, not necessarily positive definite (but generally taken to be non-degenerate). Here one is working with a vector space over the complex numbers.

Given a Hermitian form $Ψ$ on a complex vector space $V$ , the unitary group $U (Ψ)$ is the group of transforms that preserve the form: the transform $M$ such that $Ψ(M v, M w) = Ψ(v, w)$ for all $v,w\in V$ . In terms of matrices, representing the form by a matrix denoted $Φ$ , this says that $M * Φ M = Φ$ .

Just as for symmetric forms over the reals, Hermitian forms are determined by signature, and are all unitarily congruent to a diagonal form with $p$ entries of 1 on the diagonal and $q$ entries of $- 1$ . The non-degenerate assumption is equivalent to $p + q = n$ . In a standard basis, this is represented as a quadratic form as:

$\lVert z \rVert_\Psi^2 = \lVert z_1 \rVert^2 + \dots + \lVert z_p \rVert^2 - \lVert z_{p+1} \rVert^2 - \dots - \lVert z_n \rVert^2$

and as a symmetric form as:

$\Psi(w,z) = \bar w_1 z_1 + \cdots + \bar w_p z_p - \bar w_{p+1}z_{p+1} - \cdots - \bar w_n z_n$

The resulting group is denoted $U (p, q)$ .

[edit] Finite fields

Over the finite field with $q = p r$ elements, $\mathbf{F}_q$ , there is a unique degree 2 extension field, $\mathbf{F}_{q^2}$ , with order 2 automorphism $\alpha\colon x \mapsto x^q$ (the $r$ th power of the Frobenius automorphism). This allows one to define a Hermitian form on an $\mathbf{F}_{q^2}$ vector space $V$ , as an $\mathbf{F}_q$ -bilinear map $\Psi\colon V \times V \to K$ such that $\Psi(w,v)=\alpha\left(\Psi(v,w)\right)$ and $Ψ(w, c v) = c Ψ(w, v)$ for $c \in \mathbf{F}_{q^2}$ . Further, all non-degenerate Hermitian forms on a vector space over a finite field are unitarily congruent to the standard one, represented by the identity matrix, that is, any Hermetian form is unitarily equivalent to

$\Psi(w,v)=w^\alpha \cdot v = \sum_{i=1}^n w_i^q v_i$

where $w i, v i$ represent the coordinates of $w,v \in V$ in some particular $\mathbf{F}_{q^2}$ -basis of the $n$ -dimensional space $V$ (Grove 2002, Thm. 10.3).

Thus one can define a (unique) unitary group of dimension $n$ for the extension $\mathbf{F}_{q^2}/\mathbf{F}_q$ , denoted either as $U (n, q)$ or $U\left(n,q^2\right)$ depending on the author. The subgroup of the unitary group consisting of matrices of determinant 1 is called the special unitary group and denoted $S U (n, q)$ or $S U (n, q 2)$ . For convenience, this article with use the $U (n, q 2)$ convention. The center of $U (n, q 2)$ has order $q + 1$ and consists of the scalar matrices which are unitary, that is those matrices $c I V$ with $c q + 1 = 1$ . The center of the special unitary group has order $gcd(n, q + 1)$ and consists of those unitary scalars which also have order dividing $n$ . The quotient of the unitary group by its center is called the projective unitary group, $P U (n, q 2)$ , and the quotient of the special unitary group by its center is the projective special unitary group $P S U (n, q 2)$ . In most cases ( $n \geq 2$ and $(n,q^2) \notin \{ (2,2^2), (2,3^2), (3,2^2) \}$ ), $S U (n, q 2)$ is a perfect group and $P S U (n, q 2)$ is a finite simple group, (Grove 2002, Thm. 11.22 and 11.26).

[edit] Degree 2 separable algebras

More generally, given a field $k$ and a degree 2 separable $k$ -algebra $K$ (which may be a field extension but need not be), one can define unitary groups with respect to this extension.

First, there is a unique $k$ -automorphism of $K$ $a \mapsto \bar a$ which is an involution and fixes exactly $k$ ( $a=\bar a$ if and only if $a \in k$ )^[3]. This generalizes complex conjugation and the conjugation of degree 2 finite field extensions, and allows one to define Hermitian forms and unitary groups as above.

[edit] Algebraic groups

The equations defining a unitary group are polynomial equations over $k$ (but not over $K$ ): for the standard form $Φ = I$ the equations are given in matrices as $A * A = I$ , where $A^*=\overline A^t$ is the conjugate transpose. Given a different form, they are $A * Φ A = Φ$ . The unitary group is thus an algebraic group, whose points over a $k$ -algebra $R$ are given by:

$\operatorname{U}(n,K/k,\Phi)(R) := \left\{ A\in \operatorname{GL}(n,K\otimes_k R) : A^*\Phi A=\Phi\right\}$

For the field extension $\mathbf{C}/\mathbf{R}$ and the standard (positive definite) Hermitian form, these yield an algebraic group with real and complex points given by:

$\operatorname{U}(n,\mathbf{C}/\mathbf{R})(\mathbf{R}) = \operatorname{U}(n)$

$\operatorname{U}(n,\mathbf{C}/\mathbf{R})(\mathbf{C}) = \operatorname{GL}(n,\mathbf{C})$

[edit] Classifying space

The classifying space for U(n) is described in the article classifying space for U(n).

[edit] References

^ This is discussed in Arnold, "Mathematical Methods of Classical Mechanics".
^ symplectic
^ Milne, Algebraic Groups and Arithmetic Groups, p. 103

Grove, Larry C. (2002), Classical groups and geometric algebra, vol. 39, Graduate Studies in Mathematics, Providence, R.I.: American Mathematical Society, MR 1859189, ISBN 978-0-8218-2019-3

[edit] See also

Categories: Lie groups