Twisted K-theory

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In mathematics, twisted K-theory (also called "K-theory with local coefficients") is a variation on K-theory, a mathematical theory from the 1950s that spans algebraic topology, abstract algebra and operator theory.

More specifically, twisted K-theory with twist H is a particular variant of K-theory, in which the twist is given by an integral 3-dimensional cohomology class. It is special among the various twists that K-theory admits for two reasons. First, it admits a geometric formulation. This was provided in two steps ; the first one was done in 1970 (Publ. Math. de l'IHES) by Peter Donovan and Max Karoubi [1]; the second one in 1988 by Jonathan Rosenberg in Continuous-Trace Algebras from the Bundle Theoretic Point of View.

In physics, it has been conjectured to classify D-branes, Ramond-Ramond field strengths and in some cases even spinors in type II string theory. For more information on twisted K-theory in string theory, see K-theory (physics).

In the broader context of K-theory, in each subject it has numerous isomorphic formulations and, in many cases, isomorphisms relating definitions in various subjects have been proven. It also has numerous deformations, for example, in abstract algebra K-theory may be twisted by any integral cohomology class.

1 The definition
2 What is it?
3 How to Calculate It
- 3.1 Example: The Three-Sphere
4 See also
5 References

[edit] The definition

To motivate Rosenberg's geometric formulation of twisted K-theory, recall Atiyah-Janich's result that

$Fred(\mathcal H)$ ,

the Fredholm operators on Hilbert space $\mathcal H$ , is a classifying space for ordinary, untwisted K-theory. This means that the K-theory of the space M consists of the homotopy classes of maps

$[M\rightarrow Fred(\mathcal H)]$

from M to $Fred(\mathcal H)$ .

A slightly more complicated way of saying the same thing is as follows. Consider the trivial bundle of $Fred(\mathcal H)$ over M, that is, the Cartesian product of M and $Fred(\mathcal H)$ . Then the K-theory of M consists of the homotopy classes of sections of this bundle.

We can make this yet more complicated by introducing a trivial

$PU(\mathcal H)$

bundle $P$ over M, where $PU(\mathcal H)$ is the group of projective unitary operators on the Hilbert space $\mathcal H$ . Then the group of maps

$[P\rightarrow Fred(\mathcal H)]_{PU(\mathcal H)}$

from $P$ to $Fred(\mathcal H)$ which are equivariant under an action of $PU(\mathcal H)$ is equivalent to the original groups of maps

$[M\rightarrow Fred(\mathcal H)].$

This more complicated construction of ordinary K-theory is naturally generalized to the twisted case. To see this, note that $PU(\mathcal H)$ bundles on M are classified by elements H of the third integral cohomology group of M. This is a consequence of the fact that $PU(\mathcal H)$ topologically is a representative Eilenberg-MacLane space

$K(\mathbf Z,2)$ .

The generalization is then straightforward. Rosenberg has defined

K_H(M),

the twisted K-theory of M with twist given by the 3-class H, to be the space of homotopy classes of sections of the trivial $Fred(\mathcal H)$ bundle over M that are covariant with respect to a $PU(\mathcal H)$ bundle $P H$ fibered over M with 3-class H, that is

$K_H(M)=[P_H\rightarrow Fred(\mathcal H)]_{PU(\mathcal H)}.$

Equivalently, it is the space of homotopy classes of sections of the $Fred(\mathcal H)$ bundles associated to a $PU(\mathcal H)$ bundle with class H.

[edit] What is it?

When H is the trivial class, twisted K-theory is just untwisted K-theory, which is a ring. However when H is nontrivial this theory is no longer a ring. It has an addition, but it is no longer closed under multiplication.

However, the direct sum of the twisted K-theories of M with all possible twists is a ring. In particular, the product of an element of K-theory with twist H with an element of K-theory with twist H' is an element of K-theory twisted by H+H'. This element can be constructed directly from the above definition by using adjoints of Fredholm operators and construct a specific 2 x 2 matrix out of them (see the reference 1, where a more natural and general Z/2-graded version is also presented). In particular twisted K-theory is a module over classical K-theory.

[edit] How to Calculate It

If you are a physicist, you will probably want to calculate twisted K-theory using the Atiyah-Hirzebruch spectral sequence. A guide to such calculations in the case of twisted K-theory can be found in E8 Gauge Theory, and a Derivation of K-Theory from M-Theory by Emanuel Diaconescu, Gregory Moore and Edward Witten (DMW).

The idea is that one begins with all of the even or all of the odd integral cohomology, depending on whether one wishes to calculate the twisted K⁰ or the twisted K¹, and then one takes the cohomology with respect to a series of differential operators. The first operator, d₃, for example, is the sum of the three-class H, which in string theory corresponds to the Neveu-Schwarz 3-form, and the third Steenrod square. (DMW) also provide a crash course in Steenrod squares for physicists. No elementary form for the next operator, d₅, has been found, although several conjectured forms exist. Higher operators do not contribute to the K-theory of a 10-manifold, which is the dimension of interest in critical superstring theory. Over the rationals Sir Michael Atiyah and Graeme Segal have been shown that all of the differentials reduce to Massey products of H in Twisted K-theory and cohomology.

After taking the cohomology with respect to the full series of differentials one obtains twisted K-theory as a set, but to obtain the full group structure one in general needs to solve an extension problem.

[edit] Example: The Three-Sphere

The three-sphere, S³, has trivial cohomology except for H⁰(S³) and H³(S³) which are both isomorphic to the integers. Thus the even and odd cohomologies are both isomorphic to the integers. Because the three-sphere is of dimension three, which is less than five, the third Steenrod square is trivial on its cohomology and so the first nontrivial differential is just d₃=H. The later differentials increase the degree of a cohomology class by more than three and so are again trivial, thus the twisted K-theory is just the cohomology of the operator d₃ which acts on a class by cupping it with the 3-class H.

Imagine that H is the trivial class, zero. Then d₃ is also trivial. Thus its entire domain is its kernel, and nothing is in its image. Thus K⁰_H=0(S³) is the kernel of d₃ in the even cohomology, which is the full even cohomology, which consists of the integers. Similarly K¹_H=0(S³) consists of the odd cohomology quotiented by the image of d₃, in other words quotiented by the trivial group. This leaves the original odd cohomology, which is again the integers. In conclusion, K⁰ and K¹ of the three-sphere with trivial twist are both isomorphic to the integers. As expected, this agrees with the untwisted K-theory.

Now consider the case in which H is nontrivial. H is defined to be an element of the third integral cohomology, which is isomorphic to the integers. Thus H corresponds to a number, which we will call n. d₃ now takes an element m of H⁰ and yields the element nm of H³. As n is not equal to zero by assumption, the only element of the kernel of d₃ is the zero element, and so K⁰_H=n(S³)=0. The image of d₃ consists of all elements of the integers that are multiples of n. Therefore the odd cohomology, Z, quotiented by the image of d₃, nZ, is the cyclic group of order n, Z_n. In conclusion K¹_H=n(S³)=Z_n.

In string theory this result reproduces the classification of D-branes on the 3-sphere with n units of H-flux, which corresponds to the set of symmetric boundary conditions in the supersymmetric SU(2) WZW model at level n-2.

The extension of this calculation to the group manifold of SU(3) can be found in D-Brane Instantons and K-Theory Charges byJuan Maldacena, Gregory Moore and Nathan Seiberg. In this case the Steenrod square term in d₃, the operator d₅, and the extension problem are nontrivial.