User talk:Tomaxer
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Hello, Tomaxer, and welcome to Wikipedia! Thank you for your contributions. I hope you like the place and decide to stay. Here are some pages that you might find helpful:
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Also, I wanted to say thanks for the contributions you are making to chemistry articles. If you haven't seen it already, you're welcome to join the chemistry-related projects such as Wikipedia:WikiProject Chemicals and Wikipedia:WikiProject Chemistry. --Ed (Edgar181) 23:24, 10 April 2007 (UTC)
- Thanks for invitation. I have one question. I have data for chemicals as solubility or density available for temperature 20 °C, but in chembox is standard as of 25 °C. Is that OK to omit this temperature or should I still add a note about it? Tomaxer 12:20, 11 April 2007 (UTC)
- Although the difference in solubity and density at 20 vs 25 is not going to be significant, it would be best to just note the deviation from standard temp. For a density, just enter something like "1.043 g/cm3 at 20 °C" - there's an example at Butyl_butyrate. --Ed (Edgar181) 14:19, 11 April 2007 (UTC)
Contents |
[edit] Iduronic acid
Hi Tomaxer, thanks for your addition of an image to the iduronic acid article. Do you think you could draw iduronic acid in the cyclic form? This might be a more representative image. The acyclic form you've drawn and the cyclic form are in equilibrium in solution but as with glucose the cyclic form predominates. The heparin article contains a picture of a cyclic IdoA monosaccharide (see the IdoA-GlcNS or IdoA-GlcNS(6S) pictures). I'm sure you can copy the IdoA part and improve on it!! K.murphy 14:37, 27 April 2007 (UTC)
- So I've uploaded an image Image:IduronicAcid-chair.png with chair conformation projection of iduronic acid. However, I'm not very familiar with projections of sugars, so I'm not sure, if that structure is drawn correctly. If it is not, please say, what should I repair. Tomaxer 21:19, 27 April 2007 (UTC)
- Its nearly correct, although at the momment you've drawn glucose. Iduronic acid has a carboxyl group (COOH) at carbon ring position 6. Have a look at the cyclic structure shown in the glucuronic acid article. In glucuronic acid, the COOH group is attached to a carbon (carbon 5) thats also attached to a hydrogen. To turn glucuronic acid into iduronic acid swap the positioning of the COOH group and the hydrogen about carbon 5. Glucuronic acid and iduronic acid are epimers. K.murphy 15:44, 7 May 2007 (UTC)
- So, I've changed that image. I replaced CH2OH group by COOH group. I forget it when I was doing that image. I hope it is OK now, because I've got a bit unsure when you mentioned position swapping of the glucuronic acid. And is that image of the acyclic form useful? Tomaxer 17:53, 7 May 2007 (UTC)
- I was trying really hard not to confuse you, but it looks like I did it anyway!! sorry. Your change has altered glucose to glucuronic acid. At the momment the bond to the COOH is pointing upwards, you need to alter it so its pointing downwards. Personally I don't think the acyclic form is useful but its not doing any harm K.murphy 20:44, 7 May 2007 (UTC)
- New version again. Don't worry, I thought, that I should swap that COOH group. This one is a bit higher, because I had problems with overlapping bonds and COOH group. Tomaxer 15:29, 8 May 2007 (UTC)
- Nice one, the new image will do!! I'll have to learn how to use chemsketch myself K.murphy 13:42, 10 May 2007 (UTC)
- Thanks, finally I did it with your help. That ACD/Chemsketch is a good tool, I think. Working in it is in the main intuitive. If you have some questions about it, you can ask, possibly I could help you with beginning. I've learned working in it myself and some useful things are e.g. F5 (template window), Ctrl+Shift+I (IUPAC name), Tools→Generate menu, holding shift while drawing ("nice" angles, lengths). Tomaxer 13:56, 10 May 2007 (UTC)
- Nice one, the new image will do!! I'll have to learn how to use chemsketch myself K.murphy 13:42, 10 May 2007 (UTC)
- New version again. Don't worry, I thought, that I should swap that COOH group. This one is a bit higher, because I had problems with overlapping bonds and COOH group. Tomaxer 15:29, 8 May 2007 (UTC)
- I was trying really hard not to confuse you, but it looks like I did it anyway!! sorry. Your change has altered glucose to glucuronic acid. At the momment the bond to the COOH is pointing upwards, you need to alter it so its pointing downwards. Personally I don't think the acyclic form is useful but its not doing any harm K.murphy 20:44, 7 May 2007 (UTC)
- So, I've changed that image. I replaced CH2OH group by COOH group. I forget it when I was doing that image. I hope it is OK now, because I've got a bit unsure when you mentioned position swapping of the glucuronic acid. And is that image of the acyclic form useful? Tomaxer 17:53, 7 May 2007 (UTC)
- Its nearly correct, although at the momment you've drawn glucose. Iduronic acid has a carboxyl group (COOH) at carbon ring position 6. Have a look at the cyclic structure shown in the glucuronic acid article. In glucuronic acid, the COOH group is attached to a carbon (carbon 5) thats also attached to a hydrogen. To turn glucuronic acid into iduronic acid swap the positioning of the COOH group and the hydrogen about carbon 5. Glucuronic acid and iduronic acid are epimers. K.murphy 15:44, 7 May 2007 (UTC)
[edit] License tagging for Image:HomocapsaicinII.png
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[edit] Bromoform
I notice you are contributing a lot to haloalkane articles. May I ask where you got the information about the synthesis of bromoform with electrolysis? --Russoc4 16:58, 4 June 2007 (UTC)
- I found this information in book Small technical encyclopedia (translated), however, this book is from 1959, so it can be not commonly used method of preparation. But if you think, it is incorrect, feel free to remove it. But I did, a long time ago, electrolysis of potassium iodide in alcoholic solution and as far as I remember, there was produced iodoform, so it may be an analogy. However, I don't have strong theoretical chemistry knowledge, so it may be wrong. Tomaxer 17:54, 4 June 2007 (UTC)
- Well, I know the haloform reaction is the theoretical method, and I myself was investigating possibilities of producing bromine or hypobromite with electrolysis. My guess is that that method would work. I was just curious to know if you have ever been able to produce the compound. Do you have and ISBN of that book? Even though I only speak English. --Russoc4 23:48, 4 June 2007 (UTC)
- So, I've found out, that this book has no ISBN, since they started to be assigned in 1966. But it is Andrlík K., Dobrovolný B., Hoch A. A. Malý technický náučný slovník. SNTL (Státní nakladatelství technické literatury = Publishers of Technical Literature), Prague, 1959. I have scanned article about bromoform there and placed it here with translation here. And I don't remember if I have tried to produce it, but I relied on that information in this book. I can try to examine that method. Tomaxer 11:28, 5 June 2007 (UTC)
- Well, I know the haloform reaction is the theoretical method, and I myself was investigating possibilities of producing bromine or hypobromite with electrolysis. My guess is that that method would work. I was just curious to know if you have ever been able to produce the compound. Do you have and ISBN of that book? Even though I only speak English. --Russoc4 23:48, 4 June 2007 (UTC)
[edit] Dichloromethane edits
Hi, just dropping by to say that I've responded at my talk page. --Rifleman 82 15:58, 29 June 2007 (UTC)
[edit] CCl4
The aspect of most general interest is not the cell dimensions or space group, but the molecular dimensions, average C-Cl distance. You are doing nice work.--Smokefoot 23:42, 30 June 2007 (UTC)
- Yes, I known that this information is more valuable, however, I am usually able to supply only this type of data. Thanks. --Tomaxer 08:19, 1 July 2007 (UTC)
[edit] Hi
User_talk:217.68.80.50 is continuing to vandalise pages. You have warned him but he still doing it.