Talk:Shapley value

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[edit] Characterized by properties 2, 3, and 5?

Isn't property number 1 also necessary? Otherwise, you could just divide the total value of the game evenly between all the players, and this function would clearly satisfy properties 2, 3, and 5.

[edit] Properties 2, 3 and 5 do NOT characterize the Shapley value

One property is missing: If a player is null, it receives zero. A player i is null if v(S\cup \{i\}) = v(S) for all S not containg i. The Shapley value is the only value that satisfies this property, plus 2, 3, and 5. —Preceding unsigned comment added by 193.147.86.254 (talk) 17:26, 14 September 2007 (UTC)

You are right. Just take v(N) and divide it evenly among the players. This is another solution, different from the Shapley value, that satisfies 2, 3, and 5. --Fioravante Patrone en (talk) 01:19, 29 April 2008 (UTC)