Seward Township, Kosciusko County, Indiana
From Wikipedia, the free encyclopedia
Seward Township | |
Coordinates: | |
---|---|
Country | United States |
State | Indiana |
County | Kosciusko |
Area | |
- Total | 36.28 sq mi (93.96 km²) |
- Land | 35.33 sq mi (91.5 km²) |
- Water | 0.95 sq mi (2.47 km²) |
Elevation [1] | 879 ft (268 m) |
Population (2000) | |
- Total | 2,462 |
- Density | 69.69/sq mi (26.91/km²) |
FIPS code | 18-68796[2] |
GNIS feature ID | 453840 |
Seward Township is one of seventeen townships in Kosciusko County, Indiana. As of the 2000 census, its population was 2,462.
[edit] References
- ^ US Board on Geographic Names. United States Geological Survey (2007-10-25). Retrieved on 2008-01-31.
- ^ American FactFinder. United States Census Bureau. Retrieved on 2008-01-31.
[edit] External links
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