Rushbrooke inequality

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In statistical mechanics, the Rushbrooke inequality relates the critical exponents of a magnetic system which exhibits a first-order phase transition in the thermodynamic limit for non-zero temperature T.

Since the Helmholtz free energy is extensive, the normalization to free energy per site is given as

 f = -kT \lim_{N \rightarrow \infty} \frac{1}{N}\log Z_N

The magnetization M per site in the thermodynamic limit, depending on the external magnetic field H and temperature T is given by

 M(T,H) \ \stackrel{\mathrm{def}}{=}\   \lim_{N \rightarrow \infty} \frac{1}{N} \left( \sum_i \sigma_i \right) = - \left( \frac{\partial f}{\partial H} \right)_T

where σi is the spin at the i-th site, and the magnetic susceptibility and specific heat at constant temperature and field are given by, respectively

 \chi_T(T,H) = \left( \frac{\partial M}{\partial H} \right)_T

and

 c_H = -T \left( \frac{\partial^2 f}{\partial T^2} \right)_H.

[edit] Definitions

The critical exponents α,α',β,γ,γ' and δ are defined in terms of the behaviour of the order parameters and response functions near the critical point as follows

 M(t,0) \simeq (-t)^{\beta}\mbox{ for }t \uparrow 0


 M(0,H) \simeq |H|^{1/ \delta} \operatorname{sign}(H)\mbox{ for }H \rightarrow 0


 \chi_T(t,0) \simeq \begin{cases} 
	(t)^{-\gamma}, & \textrm{for} \ t \downarrow 0 \\
	(-t)^{-\gamma'}, & \textrm{for} \ t \uparrow 0 \end{cases}


 c_H(t,0) \simeq \begin{cases}
	(t)^{-\alpha} & \textrm{for} \ t \downarrow 0 \\
	(-t)^{-\alpha'} & \textrm{for} \ t \uparrow 0 \end{cases}

where

 t \ \stackrel{\mathrm{def}}{=}\   \frac{T-T_c}{T_c}

measures the temperature relative to the critical point.

[edit] Derivation

For the magnetic analogue of the Maxwell relations for the response functions, the relation

 \chi_T (c_H -c_M) = T \left( \frac{\partial M}{\partial T} \right)_H^2

follows, and with thermodynamic stability requiring that  c_h, c_M\mbox{ and }\chi_T \geq 0 , one has

 c_H \geq \frac{T}{\chi_T} \left( \frac{\partial M}{\partial T} \right)_H^2

which, under the conditions H = 0,t < 0 and the definition of the critical exponents gives

 (-t)^{-\alpha'} \geq \mathrm{constant}\cdot(-t)^{\gamma'}(-t)^{2(\beta-1)}

which gives the Rushbrooke inequality

 \alpha' + 2\beta + \gamma' \geq 2.

Remarkably, in experiment and in exactly solved models, the inequality actually holds as an equality.