Image:Ptolemy's theorem.svg

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[edit] Theorem

Diagram for geometric proof of en:Ptolemy's theorem. Created in w:Inkscape.

  1. Let ABCD be a en:cyclic quadrilateral.
  2. Note that on the en:chord BC, the en:inscribed angles ∠BAC = ∠BDC, and on AB, ∠ADB = ∠ACB.
  3. Construct K on AC such that ∠ABK = ∠CBD;
    1. Note that since ∠ABK + ∠CBK = ∠ABC = ∠CBD + ∠ABD, ∠CBK = ∠ABD.
  4. Now, by common angles △ABK is en:similar to △DBC, and likewise △ABD ∼ △KBC.
  5. Thus AK/AB = CD/BD, and CK/BC = DA/BD;
    1. Thus AK·BD = AB·CD, and CK·BD = BC·DA;
    2. Adding, (AK+CK)·BD = AB·CD + BC·DA;
    3. But AK+CK = AC, so AC·BD = AB·CD + BC·DA; en:Q.E.D.

[edit] Summary

Description

Diagram of Ptolemy's theorem

Source

Self-made

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[edit] Licensing

I, the copyright holder of this work, hereby publish it under the following licenses:
GNU head Permission is granted to copy, distribute and/or modify this document under the terms of the GNU Free Documentation license, Version 1.2 or any later version published by the Free Software Foundation; with no Invariant Sections, no Front-Cover Texts, and no Back-Cover Texts. A copy of the license is included in the section entitled "GNU Free Documentation license".

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current05:49, 28 August 2006500×164 (25 KB)EnEdC (Diagram of Ptolemy's theorem)
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