Talk:Prime ideal

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Mathematics rating: Start Class High Priority  Field: Algebra

The previously-listed statement that a subset S of a ring R is a prime ideal iff R\S is closed under multiplication was false. For example, Z\{-1,1} is clearly not an ideal since it's not closed under addition (e.g. 3-2 = 1 is not in it) but {-1,1} certainly is closed under multiplication.

The characterisation of prime ideals at the bottom of the page is incorrect - Dave Benson

I changed the bottom of the page to read that AB is a subset of P instead of AB = P. - Adam Glesser

Cool. Hi Adam. - Dave