Perpendicular axis theorem

From Wikipedia, the free encyclopedia

In physics, the perpendicular axis theorem (or plane figure theorem) can be used to determine the moment of inertia of a rigid object that lies entirely within a plane, about an axis at right angles to the plane, given the moments of inertia of the object about two perpendicular axes lying within the plane. The axes must all pass through a single point in the plane.

Define perpendicular axes X, Y, and Z (which meet at origin O) so that the body lies in the XY plane, and the Z axis is perpendicular to the plane of the body. Then let

  • IX be the moment of inertial of the body about the X axis;
  • IY be the moment of inertial of the body about the Y axis; and
  • IZ be the moment of inertial of the body about the Z axis.

Then the perpendicular axis theorem states that IZ is related to IX and IY through

IZ = IX + IY

This rule can be applied with the parallel axis theorem and the stretch rule to find moments of inertia for a variety of shapes.

[edit] Proof

Let p be a plane thin uniform lamina. Let mi be a mass element with perpendicular distance ri from an axis OZ perpendicular to the plane and passing through O in the plane.

Let OX and OY be two perpendicular axes lying in the plane. Let ai be the perpendicular distance of mi from OX and bi be the perpendicular distance of mi from OY, both in the plane. Let

I_x = \sum {m_i {a_i}^2}

be the moment of inertia of p about OX and

I_y = \sum {m_i {b_i}^2}

be the moment of inertia of p about OY. The moment of inertia of p about OZ is given by

\begin{align} I_z & = \sum {m_i {r_i}^2} \\ & = \sum {m_i \left( {a_i}^2 + {b_i}^2 \right)} \qquad \text{by the Pythagorean theorem} \\ & = \sum {m_i {a_i}^2} + \sum {m_i {b_i}^2} \\ & = I_x + I_y \end{align}

[edit] See also

Languages