Oak Grove Township, Benton County, Indiana

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Oak Grove Township
Location of Oak Grove Township in Benton County
Location of Oak Grove Township in Benton County
Coordinates: 40°31′09″N 87°15′54″W / 40.51917, -87.265
Country United States
State Indiana
County Benton
Organized July 1840
Area
 - Total 35.54 sq mi (92.04 km²)
 - Land 35.51 sq mi (91.98 km²)
 - Water 0.02 sq mi (0.06 km²)
Elevation [1] 748 ft (228 m)
Population (2000)
 - Total 1,694
 - Density 47.7/sq mi (18.42/km²)
Time zone EST (UTC-5)
 - Summer (DST) EDT (UTC-4)
FIPS code 18-55620[2]
GNIS feature ID 453681

Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2000 census, its population was 1,694. It was one of the first three townships originally created by the county's commissioners in 1840.[3] It takes its name from White Oak Grove which grew southwest of Oxford.[4]

Contents

[edit] Geography

Oak Grove Township covers an area of 35.54 square miles; 0.02 square miles (0.06 percent) of this is water.

[edit] Cities and towns

[edit] Unincorporated towns

  • Fargo (extinct)

[edit] Adjacent townships

[edit] Major highways

[edit] Cemeteries

The township contains two cemeteries: Justus and Oxford.

[edit] References

  1. ^ US Board on Geographic Names. United States Geological Survey (2007-10-25). Retrieved on 2008-01-31.
  2. ^ American FactFinder. United States Census Bureau. Retrieved on 2008-01-31.
  3. ^ Birch, Jesse Setlington [1928] (1942). History of Benton County and Historic Oxford. Oxford, Indiana: Craw & Craw, Inc., p. 20. 
  4. ^ Andreas, Alfred Theodore (1876). "Benton County", Illustrated Historical Atlas of the State of Indiana. Chicago: Baskin, Forster & Company. 


[edit] External links