Talk:Novikov conjecture

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What does \mathcal{L}_i(M) stand for? - 69.174.134.88 21:50, 9 June 2006 (UTC)

[edit] Glaring error

We supposedly have:

f: M\rightarrow BG
x \in H^{n-4i} (M;\mathbb{Q} ).
\left\langle f^*(x) \cup L_i(M),[M] \right\rangle \in \mathbb{Q}

How can we take f * (x)? Cohomology is contravariant, so f^*: H^*(BG)\rightarrow H^*(M). This mistake renders the statement of the conjecture totally non-sensical.

In the linked seminar notes there ist the same mistake. I think, x should be in H^{n-4i}(BG). This makes most sense in view of how a result of Novikov is shown to be a special case of the Novikov conjecture the seminar notes, I think. --Cardano 13:09, 12 October 2006 (UTC)

That link (as well as the mistake) was on the original page, created a year ago. Thank you, anonymous person. And Cardano you're right - the conjecture is stated in the referreed article, page 195 at http://www.maths.ed.ac.uk/~aar/books/wall1.pdf Orthografer 15:16, 12 October 2006 (UTC)