NGC 5102

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NGC 5102
Observation data (J2000 epoch)
Constellation Centaurus
Right ascension 13h 21m 57.6s[1]
Declination -36° 37′ 49″[1]
Redshift 468 ± 2 km/s[1]
Distance 12.1 ± 0.7 Mly (3.70 ± 0.23 Mpc)[2][3][4][5]
Type SA0-[1]
Apparent dimensions (V) 8′.7 × 2′.8[1]
Apparent magnitude (V) 10.4[1]
Other designations
PGC 46674[1]
See also: Galaxy, List of galaxies

NGC 5102 is a galaxy in the M83 group of galaxies. It was discovered by John Frederick William Herschel in 1835.


[edit] Distance measurements

At least two techniques have been used to measure distances to NGC 5102. The surface brightness fluctuations distance measurement technique estimates distances to spiral galaxies based on the graininess of the appearance of their bulges. The distance measured to NGC 5102 using this technique is 13.0 ± 0.8 Mly (4.0 ± 0.2 Mpc).[2] However, NGC 5102 is close enough that the tip of the red giant branch (TRGB) method may be used to estimate its distance. The estimated distance to NGC 5102 using this technique is 11.1 ± 1.3 Mly (3.40 ± 0.39 Mpc).[3] Averaged together, these distance measurements give a distance estimate of 12.1 ± 0.7 Mly (3.70 ± 0.23 Mpc).[5]

[edit] References

  1. ^ a b c d e f g NASA/IPAC Extragalactic Database. Results for NGC 5102. Retrieved on 2006-12-15.
  2. ^ a b J. L. Tonry, A. Dressler, J. P. Blakeslee, E. A. Ajhar, A. B. Fletcher, G. A. Luppino, M. R. Metzger, C. B. Moore (2001). "The SBF Survey of Galaxy Distances. IV. SBF Magnitudes, Colors, and Distances". Astrophysical Journal 546 (2): 681–693. doi:10.1086/318301. 
  3. ^ a b I. D. Karachentsev, V. E. Karachentseva, W. K. Hutchmeier, D. I. Makarov (2004). "A Catalog of Neighboring Galaxies". Astronomical Journal 127: 2031–2068. doi:10.1086/382905. 
  4. ^ Karachentsev, I. D.; Kashibadze, O. G. (2006). "Masses of the local group and of the M81 group estimated from distortions in the local velocity field". Astrophysics 49 (1): 3–18. doi:10.1007/s10511-006-0002-6. 
  5. ^ a b average(4.0 ± 0.2, 3.40 ± 0.39) = ((870 + 760) / 2) ± ((602 + 802)0.5 / 2) = 820 ± 50
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