Montmahoux
From Wikipedia, the free encyclopedia
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Commune of Montmahoux |
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| Location | ||
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| Coordinates | ||
| Administration | ||
|---|---|---|
| Country | France | |
| Region | Franche-Comté | |
| Department | Doubs | |
| Arrondissement | Besançon | |
| Canton | Amancey | |
| Intercommunality | CdC du Canton d'Amancey - Loue - Lison | |
| Statistics | ||
| Elevation | 550 m–823 m | |
| Land area¹ | 6.52 km² | |
| Population² (1999) |
67 | |
| - Density | 10/km² | |
| Miscellaneous | ||
| INSEE/Postal code | 25404/ 25270 | |
| 1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km² (0.386 sq mi or 247 acres) and river estuaries. | ||
| 2 Population sans doubles comptes: residents of multiple communes (e.g. students and military personnel) only counted once. | ||
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Montmahoux is a village and commune in the Doubs département, in the region of Franche-Comté of eastern France.
[edit] Demographics
As of the census of 1999, the population was 67.
The estimate for 2006 was 71.
[edit] See also
[edit] References
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