Talk:Metric tensor (general relativity)
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[edit] Cut material
I cut out the material on the volume form which properly belongs at volume form. Here it is for reference:
Let [g] be the matrix of elements gμν. Matrix [g] is symmetric, so due to a corollary of the spectral theorem, there exists an orthogonal transformation matrix Λ which diagonalizes [g], e.g.
where D is a diagonal matrix whose diagonal elements are eigenvalues of [g]: Dαα = λα. (Note that Λ can be chosen so that the eigenvalues are in numerical order, D00 being the smallest.) Then there is a diagonal matrix V which "unitizes" D, i.e. which applies the mapping to the diagonal elements of D. Such matrix V has diagonal elements
Then
and for a given manifold, the trace of [η] will be the same for all points and is referred to as the signature of the metric. (A signature of +2 is synonymous with a signature of (− + + +). ) This matrix [η] has the components of the Minkowski metric, which means that the manifold is, at each one of its points, locally smooth. The matrix is a Jacobian (a multivariate differential, or push forward) which transforms [η] to [g],
and taking determinants
but due to a property of diffeomorphisms, a volume element dx0dx1dx2dx3 whose factors are components of an orthonormal basis (locally), when transformed to components , has the determinant of the Jacobian matrix J as conversion factor:
See also volume form.
-- Fropuff 18:02, 22 February 2006 (UTC)
[edit] Amusing Veblen/Einstein anecdote
See Sign convention ---CH 01:54, 25 May 2006 (UTC)