Talk:Mössbauer effect

From Wikipedia, the free encyclopedia

WikiProject Physics This article is within the scope of WikiProject Physics, which collaborates on articles related to physics.
B This article has been rated as B-Class on the assessment scale.
Mid This article is on a subject of Mid importance within physics.

Help with this template This article has been rated but has no comments. If appropriate, please review the article and leave comments here to identify the strengths and weaknesses of the article and what work it will need.

Is there a reason someone removed the umlaut from Mössbauer? -- Matt Stoker

Umlauts are not Wikifiable. Meaning you can't put brackets around it and make it a link. Same goes for most special characters. --MemoryHole.com

You can make it display, just not actually link: [[Mossbauer Spectroscopy|Mössbauer Spectroscopy]] links to the first term and displays the second, like so: Mössbauer Spectroscopy. The linking is supposed to be resolved I think with .92, but I'm not sure. --KQ

Fine, but why not leave the umlauts in the unlinked text? -- Matt Stoker

With MediaWiki 1.5 we don't have such a problem anymore (as I've understood), so I just was bold moved the page a moment ago. I hope it's fine. — Pt (T) 23:27, 30 December 2005 (UTC)

- Nice articles on Mossbauer effect and spectroscopy. Upon reading that the Mars Rover uses a Mossbauer spectrometer, I was curious how elements were identified. From my college days I vaguely remembered the basic physics. Your article is a clear, concise explanation - better than other Web pages I found using a Yahoo search. - A diagram, such as http://hyperphysics.phy-astr.gsu.edu/hbase/nuclear/mossb.html, could be helpful. - Who is the author? Are you a university professor? -- PWL, 1-23-04

The article says X-rays and gamma rays behave differently, with the former able to undergo resonant emission and absorption in gasses while the latter cannot, but the article on gamma rays says they're effectively the same thing. Can anyone clarify? Specific wavelengths would be nice ^_^ 192.171.162.101 09:38, 2 August 2005 (UTC)

Note that it's not the rays which are behaving in a certain way. It's due to the properties of the gas/metal target. X- and gamma rays are both forms of electromagnetic radiation, and they do overlap somewhat, but generally speaking gamma rays have higher energy, which is why the effect happens only for gamma rays. I can't say I understand the Mossbauer effect enough to give you specific wavelengths, but I'll put it on my to-do list. You may want to check out what HyperPhysics has on this (the link in the comment above yours). - mako 02:45, 3 August 2005 (UTC)

[edit] Graph

Could someone give it English subtitles?

I'll second that request. I assume the Chinese characters say something like "Photon counts" and "Energy [MeV]" for the vertical and horizontal axes, respectively. -- JeffreyRMiles 21:20, 23 April 2007 (UTC)


[edit] Missing Stuff

There should be a notion as to why the Mößbauer Effect is so awesome that its used even though it has some very inconvienient requirements (like very low gamma decay energies for room-temperature meassurements). It would be visible in the graph, if it had english text.

The reason is: The energy resolution of the method is positively awesome. You can get resolutions in the sub- ueV range, for total energies in the 10keV range. There is no other spectroscopic methods that accurate.

[edit] His name is Rudolf Mößbauer

Its Mößbauer and not Mössbauer! —Preceding unsigned comment added by 194.8.209.3 (talk) 14:08, 14 December 2007 (UTC)

And what is the text "Meß-Bauer" supposed to achieve, aside from confusion?
—DIV (128.250.80.15 (talk) 05:05, 27 March 2008 (UTC))