Talk:Losing-Trick Count

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[edit] Far-fetched proviso

The example hand in the NLTC section:

AQ432

W         E

K8765
KQ 32
KQ52 43
32 KQ54


has received an edit that says: "[the above layout] will yield only 10 tricks if defenders cash their three aces (note: if defenders do not cash their aces, declarer may make 11 or 12 tricks)" Isn't this a bit far-fetched? How do you perceive NS to defend such that EW take 11 or even 12 tricks? JocK 21:59, 1 December 2007 (UTC)

It's not difficult to perceive a defender leading the ace of clubs or diamonds (from a doubleton) followed by a small one (hoping for a ruff); after drawing trumps, this would result in two discards (the hearts) being available and 11 tricks made. It's somewhat less likely that 12 tricks will be made but it is possible if inexperienced defenders duck too many times - unlikely I agree. Abtract 23:49, 2 December 2007 (UTC)
Even then: following a minor suit lead with the ace, how would declarer be able to make two discards? JocK (talk) 19:00, 12 December 2007 (UTC)
indeed but DA and low heart from the ace would produce 11 tricks Abtract (talk) 23:31, 12 December 2007 (UTC)
Yeah rite... and you will make grand slam if they hold up their three aces... JocK (talk) 00:42, 13 December 2007 (UTC)