Le Bizot

From Wikipedia, the free encyclopedia

Coordinates: 47°08′11″N 6°40′21″E / 47.13639, 6.6725

Commune of Le Bizot

Location
Image:Paris_plan_pointer_b_jms.gif
Map highlighting the commune of
Coordinates 47°08′11″N 6°40′21″E / 47.13639, 6.6725
Administration
Country France
Region Franche-Comté
Department Doubs
Arrondissement Montbéliard
Canton Le Russey
Intercommunality CdC du Plateau du Russey
Statistics
Elevation 887 m–1063 m
Land area¹ 7.85 km²
Population²
(1999)
198
 - Density 25/km²
Miscellaneous
INSEE/Postal code 25062/ 25210
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km² (0.386 sq mi or 247 acres) and river estuaries.
2 Population sans doubles comptes: residents of multiple communes (e.g. students and military personnel) only counted once.
France

Le Bizot is a village and commune in the Doubs département, in the Franche-Comté region of eastern France.

[edit] Demographics

As of the census of 1999, the population was 198.
The estimate for 2005 was 243.

[edit] See also

[edit] References