Talk:Lagrange multipliers/Comments

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Hey,

should it not be:

F(x,y,lambda) = f(x,y) - (lambda)*(g(x,y)-c) or f(x,y) + (lambda)*(c-g(x,y)) if g(x,y)=c. I don't know how to put mathematical expression into this form, but for an example see here: http://www.ics.mq.edu.au/~chris/math123/chap08.pdf

Ex. if f(x,y)=2xy and the constraint is x + y=1 than the Lagrangian Multiplier would be: 2xy - (lambda)*(x+y-1) or 2xy + (lambda)*(1-x-y) which is obviously the same.