Talk:Jordan's lemma
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Isn't there a restriction on the power of Jordan's Lemma? Something like, g(r) must go to 0 as fast or faster than 1/R? There's a slightly weaker theorem like 1/R^2, and then Jordan's covers all your bases. Can't find it on the web, and I don't see it here...
You don't need it 203.200.95.130 20:20, 26 August 2007 (UTC)
[edit] Error near top?
g(z)=\frac{1}{1+z^2} is a valid function for Jordan's Lemma, but g(z)=\frac{1}{z} is not.
Surely that's only for the case a=0?
I'm not sure that we should even include this case, as the references don't seem to include it as part of Jordan's lemma.