User:Jim.belk/Sandbox

From Wikipedia, the free encyclopedia

Demonstration of Template:Mbox. Try resizing your browser window to see the full effect.

Contents 1 Normal spaces 2 Non-breaking spaces 3 mbox Template 4 Use with equations

[edit] Normal spaces

i.e. ''f'': ''X'' × ''Y'' → [0, 1]

Let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1].

[edit] Non-breaking spaces

i.e. ''f'': ''X'' × ''Y'' → [0, 1]

Let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1].

[edit] mbox Template

i.e. {{nowrap| ''f'': ''X'' × ''Y'' → [0, 1]}}

Let f: X × Y → [0, 1] , and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1], and let f: X × Y → [0, 1].

[edit] Use with equations

{{nowrap|1= 2''x'' + 3''y'' + 4''z'' = 17}}

We have 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17, so 2x + 3y + 4z = 17.