Jefferson Township, Tipton County, Indiana
From Wikipedia, the free encyclopedia
Jefferson Township | |
Coordinates: | |
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Country | United States |
State | Indiana |
County | Tipton |
Area | |
- Total | 38.99 sq mi (100.99 km²) |
- Land | 38.99 sq mi (100.98 km²) |
- Water | 0 sq mi (0.01 km²) |
Elevation [1] | 919 ft (280 m) |
Population (2000) | |
- Total | 1,486 |
- Density | 38.11/sq mi (14.72/km²) |
FIPS code | 18-38250[2] |
GNIS feature ID | 453500 |
Jefferson Township is one of six townships in Tipton County, Indiana. As of the 2000 census, its population was 1,486.
[edit] References
- ^ US Board on Geographic Names. United States Geological Survey (2007-10-25). Retrieved on 2008-01-31.
- ^ American FactFinder. United States Census Bureau. Retrieved on 2008-01-31.
[edit] External links
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