Talk:Hilbert-Schmidt integral operator

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seems sensible to merge this article with Hilbert-Schmidt operator, to place this very conspicuous instance of it in context. Mct mht 09:23, 26 July 2007 (UTC)

But does an H-S integral operator necessarily have finite H-S norm? In other words, are they connected beyond sharing the same name? Sullivan.t.j 10:05, 26 July 2007 (UTC)

yes, if the kernel is square integrable. i'd guess that's the reason behind the shared name. Mct mht 10:27, 26 July 2007 (UTC)