Talk:GEO 600

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1021? or 10−21? cm? Pérez 19:29, 7 July 2006 (UTC)

This length change is a relative change of 10−21. This means that \frac{\delta l}{l} = 10^{-21}, where δl is the change in arm length, and l is the original length. Hence, if the detector arm length was 1m, the actual length change would be 10 − 21m. However, for e.g. GEO, where the arm length is 600m, a relative change of 10 − 21 corresponds to a length change of approximately 6 \times 10^{-19}m.


I apologise if the following 2 questions are meaningless:
What frequencies are prediced for gravity waves?
What gravity wave frequency range is this gravity wave detector capable of detecting?