Talk:Fibonacci polynomials

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[edit] Closed Form

This is something I discovered on my own a while back, but was unable to find much info about it online. I strongly believe that it is the closed form of the Fibonacci polynomials. I arrived at it by manipulating Binet's formula with the golden function.

I used the Wikipedia math generator to create an image for a school paper, and figured it would be a dumb idea to let the code to go to waste, so here it is:

F_n\left(x\right) = {{gold(n)^x-(n-gold(n))^x} \over {\sqrt {n^2+4}}}={{gold(n)^x-(-gold(n))^{-x}} \over {\sqrt {n^2+4}}}\

Again, I have no sources to verify/mathematically prove this, so I'm just posting it here instead. Enjoy!

--HeroofTime55 (talk) 05:56, 29 February 2008 (UTC)