Extension of scalars
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In abstract algebra, extension of scalars is a means of producing a module over a ring S from a module over another ring R, given a homomorphism between them. Intuitively, the new module admits multiplication by more scalars than the original one, hence the name extension.
[edit] Definition
In this definition the rings are assumed to be associative, but not necessarily commutative, or to have an identity. Also, modules are assumed to be left modules. The modifications needed in the case of right modules are straightforward.
Let be a homomorphism between two rings, and let M be a module over R. Consider the tensor product , where S is regarded as a right R-module via f. Since S is also a left module over itself, and the two actions commute, that is for , (in a more formal language, S is a (S,R)-bimodule), MS inherits a left action of S. It is given by for and . This module is said to be obtained from M through extension of scalars.
[edit] Interpretation as a functor
Extension of scalars can be interpreted as a functor from R-modules to S-modules. It sends M to MS, as above, and an R-homomorphism to the S-homomorphism defined by .
[edit] Connection with restriction of scalars
Consider an R-module M and an S-module N. Given a homomorphism , where N is viewed as an R-module via restriction of scalars, define to be the composition
- ,
where the last map is . This Fu is an S-homomorphism, and hence is well-defined, and is a homomorphism (of abelian groups).
In case both R and S have an identity, there is an inverse homomorphism , which is defined as follows. Let . Then Gv is the composition
- ,
where the first map is the canonical isomorphism .
This construction shows that the groups HomS(MS,N) and HomR(M,N) are isomorphic. Actually, this isomorphism depends only on the homomorphism f, and so is functorial. In the language of category theory, the extension of scalars functor is left adjoint to the restriction of scalars functor.