Douglas Township, Saunders County, Nebraska
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Douglas Township | |
Location in Saunders County | |
Coordinates: | |
---|---|
Country | United States |
State | Nebraska |
County | Saunders |
Area | |
- Total | 32.01 sq mi (82.91 km²) |
- Land | 32.01 sq mi (82.91 km²) |
- Water | 0 sq mi (0 km²) 0% |
Elevation | 1,309 ft (399 m) |
Population (2000) | |
- Total | 196 |
- Density | 6.1/sq mi (2.4/km²) |
GNIS feature ID | 0837967 |
Douglas Township is one of twenty-four townships in Saunders County, Nebraska, United States. The population was 196 at the 2000 census. A 2006 estimate placed the township's population at 205.[1]
[edit] See also
[edit] References
- ^ Subcounty population estimates: Nebraska 2000-2006 (CSV). United States Census Bureau, Population Division (2007-06-28). Retrieved on 2008-03-04.
[edit] External links
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