Displacement operator

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Quantum optics operators
Ladder operators
Creation and annihilation operators
Displacement operator
Rotation operator (quantum optics)
Squeeze operator
Anti-symmetric operator
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The displacement operator for one mode in quantum optics is the operator

$\hat{D}(\alpha)=\exp \left ( \alpha \hat{a}^\dagger - \alpha^\ast \hat{a} \right )$ ,

where $α$ is the amount of displacement in phase space, $\alpha^\ast$ is the complex cojugate of that displacement, and $\hat{a}$ and $\hat{a}^\dagger$ are the lowering and raising operators, respectively. The name of this operator is derived from its ability to display a localized state in phase space by a magnitude $α$ . It may also act on the vacuum state by displacing it into a coherent state. Specifically, $\hat{D}(\alpha)|0\rangle=|\alpha\rangle$ . Displaced states are eigenfunctions of the annihilation (lowering) operator.

1 Properties
2 Multimode displacement
3 References
4 Notes

[edit] Properties

The displacement operator is a unitary operator, and therefore obeys $\hat{D}(\alpha)\hat{D}^\dagger(\alpha)=\hat{D}^\dagger(\alpha)\hat{D}(\alpha)=I$ , where I is the identity matrix. Since $\hat{D}^\dagger(\alpha)=\hat{D}(-\alpha)$ , the hermitian conjugate of the displacement operator can also be interpreted as a displacement of opposite magnitude ( $- α$ ). The effect of applying this operator in a similarity transformation of the ladder operators results in their displacement. Specifically, this can be done by utilizing the Baker-Campbell-Hausdorff formula.

$\hat{D}^\dagger(\alpha) \hat{a} \hat{D}(\alpha)=\hat{a}+\alpha$
$\hat{D}(\alpha) \hat{a} \hat{D}^\dagger(\alpha)=\hat{a}-\alpha$

$\hat{D}(\alpha)\hat{D}(\beta)=e^{\mathrm i\cdot\operatorname{Im} \left(\alpha \beta^\ast \right)}\hat{D}(\alpha + \beta)$

When acting on an eigenket, the phase factor $e^{\mathrm i\cdot\operatorname{Im} \left(\alpha \beta^\ast \right)}$ appears in each term of the resulting state, which makes it physically irrelevant.^[1]